1000133053541 has 4 divisors (see below), whose sum is σ = 1000171382784. Its totient is φ = 1000094724300.

The previous prime is 1000133053519. The next prime is 1000133053657. The reversal of 1000133053541 is 1453503310001.

1000133053541 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1000133053541 - 2²² = 1000128859237 is a prime.

It is a super-2 number, since 2×1000133053541² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1000133053541.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1000133053511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19125455 + ... + 19177676.

It is an arithmetic number, because the mean of its divisors is an integer number (250042845696).

Almost surely, 2^{1000133053541} is an apocalyptic number.

It is an amenable number.

1000133053541 is a deficient number, since it is larger than the sum of its proper divisors (38329243).

1000133053541 is an equidigital number, since it uses as much as digits as its factorization.

1000133053541 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38329242.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 1000133053541 its reverse (1453503310001), we get a palindrome (2453636363542).

The spelling of 1000133053541 in words is "one trillion, one hundred thirty-three million, fifty-three thousand, five hundred forty-one".