1000143113 has 2 divisors, whose sum is σ = 1000143114. Its totient is φ = 1000143112.

The previous prime is 1000143091. The next prime is 1000143121. The reversal of 1000143113 is 3113410001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 862714384 + 137428729 = 29372^2 + 11723^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000143113 - 2¹⁰ = 1000142089 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1000143163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500071556 + 500071557.

It is an arithmetic number, because the mean of its divisors is an integer number (500071557).

Almost surely, 2^1000143113 is an apocalyptic number.

It is an amenable number.

1000143113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000143113 is an equidigital number, since it uses as much as digits as its factorization.

1000143113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 1000143113 is about 31625.0393359439. The cubic root of 1000143113 is about 1000.0477020578.

Adding to 1000143113 its reverse (3113410001), we get a palindrome (4113553114).

The spelling of 1000143113 in words is "one billion, one hundred forty-three thousand, one hundred thirteen".