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100020210201251 is a prime number
BaseRepresentation
bin10110101111011111000101…
…000110010111001010100011
3111010010211122102101010102222
4112233133011012113022203
5101102212342302420001
6552420352241301255
730032136023051624
oct2657370506271243
9433124572333388
10100020210201251
112996237315653a
12b27470603482b
1343a6b3323a202
141a9b00adb3a4b
15b86b4dc0c61b
hex5af7c51972a3

100020210201251 has 2 divisors, whose sum is σ = 100020210201252. Its totient is φ = 100020210201250.

The previous prime is 100020210201199. The next prime is 100020210201323. The reversal of 100020210201251 is 152102012020001.

It is a weak prime.

It is an emirp because it is prime and its reverse (152102012020001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100020210201251 is a prime.

It is a Sophie Germain prime.

It is not a weakly prime, because it can be changed into another prime (100020210201151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50010105100625 + 50010105100626.

It is an arithmetic number, because the mean of its divisors is an integer number (50010105100626).

Almost surely, 2100020210201251 is an apocalyptic number.

100020210201251 is a deficient number, since it is larger than the sum of its proper divisors (1).

100020210201251 is an equidigital number, since it uses as much as digits as its factorization.

100020210201251 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 17.

Adding to 100020210201251 its reverse (152102012020001), we get a palindrome (252122222221252).

The spelling of 100020210201251 in words is "one hundred trillion, twenty billion, two hundred ten million, two hundred one thousand, two hundred fifty-one".