10002100111 has 2 divisors, whose sum is σ = 10002100112. Its totient is φ = 10002100110.

The previous prime is 10002100081. The next prime is 10002100117. The reversal of 10002100111 is 11100120001.

It is a strong prime.

It is an emirp because it is prime and its reverse (11100120001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10002100111 - 2¹¹ = 10002098063 is a prime.

It is the 100011-st Hogben number.

It is a junction number, because it is equal to n+sod(n) for n = 10002100094 and 10002100103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10002100117) by changing a digit.

It is a nontrivial repunit in base 100010.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5001050055 + 5001050056.

It is an arithmetic number, because the mean of its divisors is an integer number (5001050056).

Almost surely, 2^10002100111 is an apocalyptic number.

10002100111 is a deficient number, since it is larger than the sum of its proper divisors (1).

10002100111 is an equidigital number, since it uses as much as digits as its factorization.

10002100111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2, while the sum is 7.

Adding to 10002100111 its reverse (11100120001), we get a palindrome (21102220112).

The spelling of 10002100111 in words is "ten billion, two million, one hundred thousand, one hundred eleven".