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100022212141 is a prime number
BaseRepresentation
bin101110100100111001…
…0011101011000101101
3100120011201102211120121
41131021302131120231
53114321141242031
6113541035044541
710140433526635
oct1351162353055
9316151384517
10100022212141
1139467a27445
12174752a0751
1395802b8a17
144babda36c5
152906176011
hex1749c9d62d

100022212141 has 2 divisors, whose sum is σ = 100022212142. Its totient is φ = 100022212140.

The previous prime is 100022212127. The next prime is 100022212181. The reversal of 100022212141 is 141212220001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99511226116 + 510986025 = 315454^2 + 22605^2 .

It is an emirp because it is prime and its reverse (141212220001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 100022212141 - 27 = 100022212013 is a prime.

It is a super-5 number, since 5×1000222121415 (a number of 56 digits) contains 55555 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100022212181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50011106070 + 50011106071.

It is an arithmetic number, because the mean of its divisors is an integer number (50011106071).

Almost surely, 2100022212141 is an apocalyptic number.

It is an amenable number.

100022212141 is a deficient number, since it is larger than the sum of its proper divisors (1).

100022212141 is an equidigital number, since it uses as much as digits as its factorization.

100022212141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 100022212141 its reverse (141212220001), we get a palindrome (241234432142).

The spelling of 100022212141 in words is "one hundred billion, twenty-two million, two hundred twelve thousand, one hundred forty-one".