10002300000013 has 4 divisors (see below), whose sum is σ = 10034880782080. Its totient is φ = 9969719217948.

The previous prime is 10002299999963. The next prime is 10002300000053. The reversal of 10002300000013 is 31000000320001.

10002300000013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10002300000013 - 2³³ = 9993710065421 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10002300000053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16290390573 + ... + 16290391186.

It is an arithmetic number, because the mean of its divisors is an integer number (2508720195520).

Almost surely, 2^{10002300000013} is an apocalyptic number.

It is an amenable number.

10002300000013 is a deficient number, since it is larger than the sum of its proper divisors (32580782067).

10002300000013 is an equidigital number, since it uses as much as digits as its factorization.

10002300000013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32580782066.

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 10002300000013 its reverse (31000000320001), we get a palindrome (41002300320014).

The spelling of 10002300000013 in words is "ten trillion, two billion, three hundred million, thirteen", and thus it is an aban number.