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100023033113 is a prime number
BaseRepresentation
bin101110100100111010…
…1100101110100011001
3100120011202222112201222
41131021311211310121
53114321344024423
6113541104421425
710140443516303
oct1351165456431
9316152875658
10100023033113
1139468438233
1217475617875
1395805155c3
144bac138973
1529062893c8
hex1749d65d19

100023033113 has 2 divisors, whose sum is σ = 100023033114. Its totient is φ = 100023033112.

The previous prime is 100023033101. The next prime is 100023033137. The reversal of 100023033113 is 311330320001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 76744512784 + 23278520329 = 277028^2 + 152573^2 .

It is a cyclic number.

It is not a de Polignac number, because 100023033113 - 220 = 100021984537 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100023033091 and 100023033100.

It is not a weakly prime, because it can be changed into another prime (100023033013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50011516556 + 50011516557.

It is an arithmetic number, because the mean of its divisors is an integer number (50011516557).

Almost surely, 2100023033113 is an apocalyptic number.

It is an amenable number.

100023033113 is a deficient number, since it is larger than the sum of its proper divisors (1).

100023033113 is an equidigital number, since it uses as much as digits as its factorization.

100023033113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 100023033113 its reverse (311330320001), we get a palindrome (411353353114).

The spelling of 100023033113 in words is "one hundred billion, twenty-three million, thirty-three thousand, one hundred thirteen".