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100023112113 = 3119872781433
BaseRepresentation
bin101110100100111010…
…1111001000110110001
3100120011210010120002220
41131021311321012301
53114321404041423
6113541110231253
710140444265521
oct1351165710661
9316153116086
10100023112113
1139468491621
1217475655529
139580542552
144bac159681
1529062a29e3
hex1749d791b1

100023112113 has 8 divisors (see below), whose sum is σ = 133375323168. Its totient is φ = 66676487904.

The previous prime is 100023112081. The next prime is 100023112129. The reversal of 100023112113 is 311211320001.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 100023112113 - 25 = 100023112081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100023112092 and 100023112101.

It is not an unprimeable number, because it can be changed into a prime (100023112183) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1354756 + ... + 1426677.

It is an arithmetic number, because the mean of its divisors is an integer number (16671915396).

Almost surely, 2100023112113 is an apocalyptic number.

It is an amenable number.

100023112113 is a deficient number, since it is larger than the sum of its proper divisors (33352211055).

100023112113 is a wasteful number, since it uses less digits than its factorization.

100023112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2793423.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 100023112113 its reverse (311211320001), we get a palindrome (411234432114).

The spelling of 100023112113 in words is "one hundred billion, twenty-three million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 3 11987 35961 2781433 8344299 33341037371 100023112113