1000251481 has 2 divisors, whose sum is σ = 1000251482. Its totient is φ = 1000251480.

The previous prime is 1000251449. The next prime is 1000251503. The reversal of 1000251481 is 1841520001.

It is an a-pointer prime, because the next prime (1000251503) can be obtained adding 1000251481 to its sum of digits (22).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 707294025 + 292957456 = 26595^2 + 17116^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000251481 - 2⁵ = 1000251449 is a prime.

It is a super-2 number, since 2×1000251481² = 2001006050485386722, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1000254481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500125740 + 500125741.

It is an arithmetic number, because the mean of its divisors is an integer number (500125741).

Almost surely, 2^1000251481 is an apocalyptic number.

It is an amenable number.

1000251481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000251481 is an equidigital number, since it uses as much as digits as its factorization.

1000251481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 320, while the sum is 22.

The square root of 1000251481 is about 31626.7526154678. The cubic root of 1000251481 is about 1000.0838199740.

Adding to 1000251481 its reverse (1841520001), we get a palindrome (2841771482).

The spelling of 1000251481 in words is "one billion, two hundred fifty-one thousand, four hundred eighty-one".