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100031122738957 is a prime number
BaseRepresentation
bin10110101111101001001111…
…100010011000111100001101
3111010011212210221020110222011
4112233221033202120330031
5101102402214410121312
6552425355143021221
730033003321101434
oct2657511742307415
9433155727213864
10100031122738957
1129966a62a86643
12b27685073a811
1343a7b81cc0a07
141a9b7643d811b
15b8708bc71da7
hex5afa4f898f0d

100031122738957 has 2 divisors, whose sum is σ = 100031122738958. Its totient is φ = 100031122738956.

The previous prime is 100031122738909. The next prime is 100031122739017. The reversal of 100031122738957 is 759837221130001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 54984286389321 + 45046836349636 = 7415139^2 + 6711694^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100031122738957 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100031122738957.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100031122768957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50015561369478 + 50015561369479.

It is an arithmetic number, because the mean of its divisors is an integer number (50015561369479).

Almost surely, 2100031122738957 is an apocalyptic number.

It is an amenable number.

100031122738957 is a deficient number, since it is larger than the sum of its proper divisors (1).

100031122738957 is an equidigital number, since it uses as much as digits as its factorization.

100031122738957 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 635040, while the sum is 49.

Adding to 100031122738957 its reverse (759837221130001), we get a palindrome (859868343868958).

The spelling of 100031122738957 in words is "one hundred trillion, thirty-one billion, one hundred twenty-two million, seven hundred thirty-eight thousand, nine hundred fifty-seven".