Base | Representation |
---|---|
bin | 10110101111101001001111… |
… | …100011011000111001111111 |
3 | 111010011212210221201210100221 |
4 | 112233221033203120321333 |
5 | 101102402214442012314 |
6 | 552425355152402211 |
7 | 30033003323242333 |
oct | 2657511743307177 |
9 | 433155727653327 |
10 | 100031123000959 |
11 | 29966a63145477 |
12 | b276850846367 |
13 | 43a7b82083047 |
14 | 1a9b7644657c3 |
15 | b8708bcc4824 |
hex | 5afa4f8d8e7f |
100031123000959 has 2 divisors, whose sum is σ = 100031123000960. Its totient is φ = 100031123000958.
The previous prime is 100031123000947. The next prime is 100031123001109. The reversal of 100031123000959 is 959000321130001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100031123000959 - 233 = 100022533066367 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100031123000059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50015561500479 + 50015561500480.
It is an arithmetic number, because the mean of its divisors is an integer number (50015561500480).
Almost surely, 2100031123000959 is an apocalyptic number.
100031123000959 is a deficient number, since it is larger than the sum of its proper divisors (1).
100031123000959 is an equidigital number, since it uses as much as digits as its factorization.
100031123000959 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7290, while the sum is 34.
The spelling of 100031123000959 in words is "one hundred trillion, thirty-one billion, one hundred twenty-three million, nine hundred fifty-nine", and thus it is an aban number.
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