Base | Representation |
---|---|
bin | 11101000111001110011… |
… | …00100000111000111011 |
3 | 10112121222102001112210111 |
4 | 32203213030200320323 |
5 | 112342114133330021 |
6 | 2043311525125151 |
7 | 132161434110112 |
oct | 16434714407073 |
9 | 3477872045714 |
10 | 1000311230011 |
11 | 35625867a685 |
12 | 141a4a2597b7 |
13 | 734378c9002 |
14 | 365b5900c79 |
15 | 1b048c428e1 |
hex | e8e7320e3b |
1000311230011 has 2 divisors, whose sum is σ = 1000311230012. Its totient is φ = 1000311230010.
The previous prime is 1000311229999. The next prime is 1000311230021. The reversal of 1000311230011 is 1100321130001.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1000311230011 - 223 = 1000302841403 is a prime.
It is a super-2 number, since 2×10003112300112 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1000311229973 and 1000311230000.
It is not a weakly prime, because it can be changed into another prime (1000311230021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500155615005 + 500155615006.
It is an arithmetic number, because the mean of its divisors is an integer number (500155615006).
Almost surely, 21000311230011 is an apocalyptic number.
1000311230011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000311230011 is an equidigital number, since it uses as much as digits as its factorization.
1000311230011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1000311230011 its reverse (1100321130001), we get a palindrome (2100632360012).
The spelling of 1000311230011 in words is "one trillion, three hundred eleven million, two hundred thirty thousand, eleven".
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