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100031220041 is a prime number
BaseRepresentation
bin101110100101001010…
…0110100100101001001
3100120012100101111002112
41131022110310211021
53114330443020131
6113542000112105
710140603225014
oct1351224644511
9316170344075
10100031220041
113947201a195
1217478305635
139582120b3c
144bad26a37b
152906d5502b
hex174a534949

100031220041 has 2 divisors, whose sum is σ = 100031220042. Its totient is φ = 100031220040.

The previous prime is 100031219941. The next prime is 100031220139. The reversal of 100031220041 is 140022130001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95108092816 + 4923127225 = 308396^2 + 70165^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-100031220041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 100031219998 and 100031220025.

It is not a weakly prime, because it can be changed into another prime (100031223041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50015610020 + 50015610021.

It is an arithmetic number, because the mean of its divisors is an integer number (50015610021).

Almost surely, 2100031220041 is an apocalyptic number.

It is an amenable number.

100031220041 is a deficient number, since it is larger than the sum of its proper divisors (1).

100031220041 is an equidigital number, since it uses as much as digits as its factorization.

100031220041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 100031220041 its reverse (140022130001), we get a palindrome (240053350042).

The spelling of 100031220041 in words is "one hundred billion, thirty-one million, two hundred twenty thousand, forty-one".