1000314911 has 2 divisors, whose sum is σ = 1000314912. Its totient is φ = 1000314910.

The previous prime is 1000314899. The next prime is 1000314979. The reversal of 1000314911 is 1194130001.

It is a weak prime.

It is an emirp because it is prime and its reverse (1194130001) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000314911 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000311911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500157455 + 500157456.

It is an arithmetic number, because the mean of its divisors is an integer number (500157456).

Almost surely, 2^1000314911 is an apocalyptic number.

1000314911 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000314911 is an equidigital number, since it uses as much as digits as its factorization.

1000314911 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 20.

The square root of 1000314911 is about 31627.7553898471. The cubic root of 1000314911 is about 1000.1049593165.

Adding to 1000314911 its reverse (1194130001), we get a palindrome (2194444912).

The spelling of 1000314911 in words is "one billion, three hundred fourteen thousand, nine hundred eleven".