100032013100011 has 4 divisors (see below), whose sum is σ = 100032083043552. Its totient is φ = 100031943156472.

The previous prime is 100032013099979. The next prime is 100032013100069. The reversal of 100032013100011 is 110001310230001.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 100032013100011 - 2⁵ = 100032013099979 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100032013099964 and 100032013100000.

It is not an unprimeable number, because it can be changed into a prime (100032013104011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32780740 + ... + 35702113.

It is an arithmetic number, because the mean of its divisors is an integer number (25008020760888).

Almost surely, 2^{100032013100011} is an apocalyptic number.

100032013100011 is a deficient number, since it is larger than the sum of its proper divisors (69943541).

100032013100011 is an equidigital number, since it uses as much as digits as its factorization.

100032013100011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69943540.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 100032013100011 its reverse (110001310230001), we get a palindrome (210033323330012).

The spelling of 100032013100011 in words is "one hundred trillion, thirty-two billion, thirteen million, one hundred thousand, eleven".