Base | Representation |
---|---|
bin | 11101000111010000110… |
… | …00110100000001001111 |
3 | 10112122000210200201102101 |
4 | 32203220120310001033 |
5 | 112342134243400221 |
6 | 2043313521535531 |
7 | 132162066112666 |
oct | 16435030640117 |
9 | 3478023621371 |
10 | 1000331231311 |
11 | 3562689a0985 |
12 | 141a54aa45a7 |
13 | 7343baacbb9 |
14 | 365b8429ddd |
15 | 1b04a893d91 |
hex | e8e863404f |
1000331231311 has 2 divisors, whose sum is σ = 1000331231312. Its totient is φ = 1000331231310.
The previous prime is 1000331231279. The next prime is 1000331231329. The reversal of 1000331231311 is 1131321330001.
It is a strong prime.
It is an emirp because it is prime and its reverse (1131321330001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1000331231311 - 25 = 1000331231279 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000331231351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500165615655 + 500165615656.
It is an arithmetic number, because the mean of its divisors is an integer number (500165615656).
Almost surely, 21000331231311 is an apocalyptic number.
1000331231311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000331231311 is an equidigital number, since it uses as much as digits as its factorization.
1000331231311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1000331231311 its reverse (1131321330001), we get a palindrome (2131652561312).
The spelling of 1000331231311 in words is "one trillion, three hundred thirty-one million, two hundred thirty-one thousand, three hundred eleven".
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