Base | Representation |
---|---|
bin | 10110101111101100000011… |
… | …011101101010110010011111 |
3 | 111010012011121022101100202021 |
4 | 112233230003131222302133 |
5 | 101102424410144301343 |
6 | 552431014455241011 |
7 | 30033141164226232 |
oct | 2657540335526237 |
9 | 433164538340667 |
10 | 100034141400223 |
11 | 29968271a32518 |
12 | b277353679167 |
13 | 43a824350a204 |
14 | 1a9b96d29b419 |
15 | b871b6ca00ed |
hex | 5afb0376ac9f |
100034141400223 has 2 divisors, whose sum is σ = 100034141400224. Its totient is φ = 100034141400222.
The previous prime is 100034141400121. The next prime is 100034141400367. The reversal of 100034141400223 is 322004141430001.
It is a weak prime.
It is an emirp because it is prime and its reverse (322004141430001) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100034141400223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100034141800223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50017070700111 + 50017070700112.
It is an arithmetic number, because the mean of its divisors is an integer number (50017070700112).
Almost surely, 2100034141400223 is an apocalyptic number.
100034141400223 is a deficient number, since it is larger than the sum of its proper divisors (1).
100034141400223 is an equidigital number, since it uses as much as digits as its factorization.
100034141400223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 100034141400223 its reverse (322004141430001), we get a palindrome (422038282830224).
The spelling of 100034141400223 in words is "one hundred trillion, thirty-four billion, one hundred forty-one million, four hundred thousand, two hundred twenty-three".
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