Base | Representation |
---|---|
bin | 11101000111011000111… |
… | …11100110110100111111 |
3 | 10112122012121022200111221 |
4 | 32203230133212310333 |
5 | 112342304412334101 |
6 | 2043324422254211 |
7 | 132163563504004 |
oct | 16435437466477 |
9 | 3478177280457 |
10 | 1000400121151 |
11 | 3562a3873932 |
12 | 141a73b87367 |
13 | 73450150312 |
14 | 365c363d8ab |
15 | 1b051950aa1 |
hex | e8ec7e6d3f |
1000400121151 has 2 divisors, whose sum is σ = 1000400121152. Its totient is φ = 1000400121150.
The previous prime is 1000400121131. The next prime is 1000400121179. The reversal of 1000400121151 is 1511210040001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1000400121151 - 219 = 1000399596863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000400121131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500200060575 + 500200060576.
It is an arithmetic number, because the mean of its divisors is an integer number (500200060576).
Almost surely, 21000400121151 is an apocalyptic number.
1000400121151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000400121151 is an equidigital number, since it uses as much as digits as its factorization.
1000400121151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 16.
Adding to 1000400121151 its reverse (1511210040001), we get a palindrome (2511610161152).
The spelling of 1000400121151 in words is "one trillion, four hundred million, one hundred twenty-one thousand, one hundred fifty-one".
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