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100040124001 = 711409015831
BaseRepresentation
bin101110100101011011…
…0110010011001100001
3100120012222010212000211
41131022312302121201
53114340232432001
6113542515014121
710141042011046
oct1351266623141
9316188125024
10100040124001
1139477050934
121747b29a341
139583c1a85c
144bb05071cd
152907a13351
hex174adb2661

100040124001 has 4 divisors (see below), whose sum is σ = 101449139904. Its totient is φ = 98631108100.

The previous prime is 100040123969. The next prime is 100040124011. The reversal of 100040124001 is 100421040001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100040124001 - 25 = 100040123969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (100040124011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 704507845 + ... + 704507986.

It is an arithmetic number, because the mean of its divisors is an integer number (25362284976).

Almost surely, 2100040124001 is an apocalyptic number.

It is an amenable number.

100040124001 is a deficient number, since it is larger than the sum of its proper divisors (1409015903).

100040124001 is an equidigital number, since it uses as much as digits as its factorization.

100040124001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1409015902.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 100040124001 its reverse (100421040001), we get a palindrome (200461164002).

The spelling of 100040124001 in words is "one hundred billion, forty million, one hundred twenty-four thousand, one".

Divisors: 1 71 1409015831 100040124001