Base | Representation |
---|---|
bin | 1001000110010100001110… |
… | …1111010010010000010111 |
3 | 1022102101100222220020001201 |
4 | 2101211003233102100113 |
5 | 2302401412004121044 |
6 | 33135454354133331 |
7 | 2051526206002462 |
oct | 221450357222027 |
9 | 38371328806051 |
10 | 10004115301399 |
11 | 32077a330a95a |
12 | 1156a45b81247 |
13 | 5774cb91a2cb |
14 | 2682b78d82d9 |
15 | 12536b3917d4 |
hex | 91943bd2417 |
10004115301399 has 2 divisors, whose sum is σ = 10004115301400. Its totient is φ = 10004115301398.
The previous prime is 10004115301391. The next prime is 10004115301409. The reversal of 10004115301399 is 99310351140001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10004115301399 - 23 = 10004115301391 is a prime.
It is a super-2 number, since 2×100041153013992 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10004115301391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002057650699 + 5002057650700.
It is an arithmetic number, because the mean of its divisors is an integer number (5002057650700).
Almost surely, 210004115301399 is an apocalyptic number.
10004115301399 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004115301399 is an equidigital number, since it uses as much as digits as its factorization.
10004115301399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 37.
The spelling of 10004115301399 in words is "ten trillion, four billion, one hundred fifteen million, three hundred one thousand, three hundred ninety-nine".
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