100041313 has 4 divisors (see below), whose sum is σ = 100163988. Its totient is φ = 99918640.

The previous prime is 100041307. The next prime is 100041323. The reversal of 100041313 is 313140001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 313140001 = 41 ⋅7637561.

It can be written as a sum of positive squares in 2 ways, for example, as 66308449 + 33732864 = 8143^2 + 5808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-100041313 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 100041293 and 100041302.

It is not an unprimeable number, because it can be changed into a prime (100041323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60106 + ... + 61747.

It is an arithmetic number, because the mean of its divisors is an integer number (25040997).

Almost surely, 2^100041313 is an apocalyptic number.

It is an amenable number.

100041313 is a deficient number, since it is larger than the sum of its proper divisors (122675).

100041313 is an equidigital number, since it uses as much as digits as its factorization.

100041313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 122674.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 100041313 is about 10002.0654366986. The cubic root of 100041313 is about 464.2227938808. Note that the first 3 decimals are identical.

Adding to 100041313 its reverse (313140001), we get a palindrome (413181314).

The spelling of 100041313 in words is "one hundred million, forty-one thousand, three hundred thirteen".