Base | Representation |
---|---|
bin | 101110100101011101… |
… | …1101110110011000011 |
3 | 100120020001120200202201 |
4 | 1131022323232303003 |
5 | 3114341100414341 |
6 | 113543002454031 |
7 | 10141056016303 |
oct | 1351273566303 |
9 | 316201520681 |
10 | 100041419971 |
11 | 39477856589 |
12 | 1747b804317 |
13 | 95842826bc |
14 | 4bb0763603 |
15 | 2907bbc331 |
hex | 174aeeecc3 |
100041419971 has 2 divisors, whose sum is σ = 100041419972. Its totient is φ = 100041419970.
The previous prime is 100041419969. The next prime is 100041420023. The reversal of 100041419971 is 179914140001.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 100041419971 - 21 = 100041419969 is a prime.
It is a super-3 number, since 3×1000414199713 (a number of 34 digits) contains 333 as substring.
Together with 100041419969, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 100041419971.
It is not a weakly prime, because it can be changed into another prime (100041419941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50020709985 + 50020709986.
It is an arithmetic number, because the mean of its divisors is an integer number (50020709986).
Almost surely, 2100041419971 is an apocalyptic number.
100041419971 is a deficient number, since it is larger than the sum of its proper divisors (1).
100041419971 is an equidigital number, since it uses as much as digits as its factorization.
100041419971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 37.
Adding to 100041419971 its reverse (179914140001), we get a palindrome (279955559972).
The spelling of 100041419971 in words is "one hundred billion, forty-one million, four hundred nineteen thousand, nine hundred seventy-one".
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