10004143481 has 2 divisors, whose sum is σ = 10004143482. Its totient is φ = 10004143480.

The previous prime is 10004143451. The next prime is 10004143573. The reversal of 10004143481 is 18434140001.

10004143481 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7676563456 + 2327580025 = 87616^2 + 48245^2 .

It is a cyclic number.

It is not a de Polignac number, because 10004143481 - 2¹⁸ = 10003881337 is a prime.

It is a super-2 number, since 2×10004143481² (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 10004143481.

It is not a weakly prime, because it can be changed into another prime (10004143421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002071740 + 5002071741.

It is an arithmetic number, because the mean of its divisors is an integer number (5002071741).

Almost surely, 2^10004143481 is an apocalyptic number.

It is an amenable number.

10004143481 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004143481 is an equidigital number, since it uses as much as digits as its factorization.

10004143481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 10004143481 its reverse (18434140001), we get a palindrome (28438283482).

The spelling of 10004143481 in words is "ten billion, four million, one hundred forty-three thousand, four hundred eighty-one".