1000424113 has 4 divisors (see below), whose sum is σ = 1077379828. Its totient is φ = 923468400.

The previous prime is 1000424099. The next prime is 1000424129. The reversal of 1000424113 is 3114240001.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3114240001 = 22637 ⋅137573.

It can be written as a sum of positive squares in 2 ways, for example, as 92486689 + 907937424 = 9617^2 + 30132^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000424113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1000425113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38477838 + ... + 38477863.

It is an arithmetic number, because the mean of its divisors is an integer number (269344957).

Almost surely, 2^1000424113 is an apocalyptic number.

1000424113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1000424113 is a deficient number, since it is larger than the sum of its proper divisors (76955715).

1000424113 is an equidigital number, since it uses as much as digits as its factorization.

1000424113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 76955714.

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1000424113 is about 31629.4817061551. The cubic root of 1000424113 is about 1000.1413510189.

Adding to 1000424113 its reverse (3114240001), we get a palindrome (4114664114).

The spelling of 1000424113 in words is "one billion, four hundred twenty-four thousand, one hundred thirteen".