1000425121 has 2 divisors, whose sum is σ = 1000425122. Its totient is φ = 1000425120.

The previous prime is 1000425119. The next prime is 1000425131. The reversal of 1000425121 is 1215240001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 978438400 + 21986721 = 31280^2 + 4689^2 .

It is a cyclic number.

It is not a de Polignac number, because 1000425121 - 2¹ = 1000425119 is a prime.

Together with 1000425119, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1000425095 and 1000425104.

It is not a weakly prime, because it can be changed into another prime (1000425131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500212560 + 500212561.

It is an arithmetic number, because the mean of its divisors is an integer number (500212561).

Almost surely, 2^1000425121 is an apocalyptic number.

It is an amenable number.

1000425121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000425121 is an equidigital number, since it uses as much as digits as its factorization.

1000425121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80, while the sum is 16.

The square root of 1000425121 is about 31629.4976406518. The cubic root of 1000425121 is about 1000.1416869239.

Adding to 1000425121 its reverse (1215240001), we get a palindrome (2215665122).

The spelling of 1000425121 in words is "one billion, four hundred twenty-five thousand, one hundred twenty-one".