1000433439991 has 2 divisors, whose sum is σ = 1000433439992. Its totient is φ = 1000433439990.

The previous prime is 1000433439911. The next prime is 1000433440007. The reversal of 1000433439991 is 1999343340001.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1000433439991 is a prime.

It is a super-4 number, since 4×1000433439991⁴ (a number of 49 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1000433439911) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500216719995 + 500216719996.

It is an arithmetic number, because the mean of its divisors is an integer number (500216719996).

Almost surely, 2^{1000433439991} is an apocalyptic number.

1000433439991 is a deficient number, since it is larger than the sum of its proper divisors (1).

1000433439991 is an equidigital number, since it uses as much as digits as its factorization.

1000433439991 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 314928, while the sum is 46.

Adding to 1000433439991 its reverse (1999343340001), we get a palindrome (2999776779992).

The spelling of 1000433439991 in words is "one trillion, four hundred thirty-three million, four hundred thirty-nine thousand, nine hundred ninety-one".