Base | Representation |
---|---|
bin | 1001000110010101000100… |
… | …1000011100101000011011 |
3 | 1022102101221122201011101112 |
4 | 2101211101020130220123 |
5 | 2302402342020020212 |
6 | 33135532542210535 |
7 | 2051534604632321 |
oct | 221452110345033 |
9 | 38371848634345 |
10 | 10004340001307 |
11 | 32078a9133263 |
12 | 1156aa9283a4b |
13 | 577536342032 |
14 | 2682d96a9d11 |
15 | 125380e79422 |
hex | 9195121ca1b |
10004340001307 has 2 divisors, whose sum is σ = 10004340001308. Its totient is φ = 10004340001306.
The previous prime is 10004340001301. The next prime is 10004340001363. The reversal of 10004340001307 is 70310004340001.
It is a weak prime.
It is an emirp because it is prime and its reverse (70310004340001) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10004340001307 - 222 = 10004335807003 is a prime.
It is not a weakly prime, because it can be changed into another prime (10004340001301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002170000653 + 5002170000654.
It is an arithmetic number, because the mean of its divisors is an integer number (5002170000654).
Almost surely, 210004340001307 is an apocalyptic number.
10004340001307 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004340001307 is an equidigital number, since it uses as much as digits as its factorization.
10004340001307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 23.
Adding to 10004340001307 its reverse (70310004340001), we get a palindrome (80314344341308).
The spelling of 10004340001307 in words is "ten trillion, four billion, three hundred forty million, one thousand, three hundred seven".
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