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100043421 = 333347807
BaseRepresentation
bin1011111011010…
…00101010011101
320222020201202220
411331220222131
5201102342141
613532135553
72323232532
oct575505235
9228221686
10100043421
1151521115
12296075b9
131795a4ba
14d402d89
158bb2766
hex5f68a9d

100043421 has 4 divisors (see below), whose sum is σ = 133391232. Its totient is φ = 66695612.

The previous prime is 100043393. The next prime is 100043423. The reversal of 100043421 is 124340001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 100043421 - 26 = 100043357 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 100043421.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (100043423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16673901 + ... + 16673906.

It is an arithmetic number, because the mean of its divisors is an integer number (33347808).

Almost surely, 2100043421 is an apocalyptic number.

It is an amenable number.

100043421 is a deficient number, since it is larger than the sum of its proper divisors (33347811).

100043421 is an equidigital number, since it uses as much as digits as its factorization.

100043421 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 33347810.

The product of its (nonzero) digits is 96, while the sum is 15.

The square root of 100043421 is about 10002.1708143782. The cubic root of 100043421 is about 464.2260544497.

Adding to 100043421 its reverse (124340001), we get a palindrome (224383422).

The spelling of 100043421 in words is "one hundred million, forty-three thousand, four hundred twenty-one".

Divisors: 1 3 33347807 100043421