Base | Representation |
---|---|
bin | 1001000110010101010011… |
… | …0101011000111101010011 |
3 | 1022102102002222120211111222 |
4 | 2101211110311120331103 |
5 | 2302403003420130022 |
6 | 33135543041355255 |
7 | 2051536260610112 |
oct | 221452465307523 |
9 | 38372088524458 |
10 | 10004402114387 |
11 | 32079301a778a |
12 | 1156b06038b2b |
13 | 57754617ba35 |
14 | 268303a37c79 |
15 | 125386648242 |
hex | 91954d58f53 |
10004402114387 has 2 divisors, whose sum is σ = 10004402114388. Its totient is φ = 10004402114386.
The previous prime is 10004402114353. The next prime is 10004402114389. The reversal of 10004402114387 is 78341120440001.
10004402114387 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10004402114387 is a prime.
Together with 10004402114389, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10004402114389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002201057193 + 5002201057194.
It is an arithmetic number, because the mean of its divisors is an integer number (5002201057194).
Almost surely, 210004402114387 is an apocalyptic number.
10004402114387 is a deficient number, since it is larger than the sum of its proper divisors (1).
10004402114387 is an equidigital number, since it uses as much as digits as its factorization.
10004402114387 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 35.
Adding to 10004402114387 its reverse (78341120440001), we get a palindrome (88345522554388).
The spelling of 10004402114387 in words is "ten trillion, four billion, four hundred two million, one hundred fourteen thousand, three hundred eighty-seven".
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