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10004402114387 is a prime number
BaseRepresentation
bin1001000110010101010011…
…0101011000111101010011
31022102102002222120211111222
42101211110311120331103
52302403003420130022
633135543041355255
72051536260610112
oct221452465307523
938372088524458
1010004402114387
1132079301a778a
121156b06038b2b
1357754617ba35
14268303a37c79
15125386648242
hex91954d58f53

10004402114387 has 2 divisors, whose sum is σ = 10004402114388. Its totient is φ = 10004402114386.

The previous prime is 10004402114353. The next prime is 10004402114389. The reversal of 10004402114387 is 78341120440001.

10004402114387 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10004402114387 is a prime.

Together with 10004402114389, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (10004402114389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002201057193 + 5002201057194.

It is an arithmetic number, because the mean of its divisors is an integer number (5002201057194).

Almost surely, 210004402114387 is an apocalyptic number.

10004402114387 is a deficient number, since it is larger than the sum of its proper divisors (1).

10004402114387 is an equidigital number, since it uses as much as digits as its factorization.

10004402114387 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21504, while the sum is 35.

Adding to 10004402114387 its reverse (78341120440001), we get a palindrome (88345522554388).

The spelling of 10004402114387 in words is "ten trillion, four billion, four hundred two million, one hundred fourteen thousand, three hundred eighty-seven".