Base | Representation |
---|---|
bin | 1001000110010101010110… |
… | …0011001100000001001101 |
3 | 1022102102010211011210010210 |
4 | 2101211111203030001031 |
5 | 2302403020003320023 |
6 | 33135544150553033 |
7 | 2051536464631665 |
oct | 221452543140115 |
9 | 38372124153123 |
10 | 10004414120013 |
11 | 3207936a57795 |
12 | 1156b0a068779 |
13 | 5775487c3461 |
14 | 2683054811a5 |
15 | 12538771a593 |
hex | 919558cc04d |
10004414120013 has 4 divisors (see below), whose sum is σ = 13339218826688. Its totient is φ = 6669609413340.
The previous prime is 10004414119951. The next prime is 10004414120059. The reversal of 10004414120013 is 31002141440001.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 10004414120013 - 217 = 10004413988941 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10004414120083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1667402353333 + ... + 1667402353338.
It is an arithmetic number, because the mean of its divisors is an integer number (3334804706672).
Almost surely, 210004414120013 is an apocalyptic number.
It is an amenable number.
10004414120013 is a deficient number, since it is larger than the sum of its proper divisors (3334804706675).
10004414120013 is an equidigital number, since it uses as much as digits as its factorization.
10004414120013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3334804706674.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 10004414120013 its reverse (31002141440001), we get a palindrome (41006555560014).
The spelling of 10004414120013 in words is "ten trillion, four billion, four hundred fourteen million, one hundred twenty thousand, thirteen".
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