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10004420143 = 12037831139
BaseRepresentation
bin10010101000100111…
…10101011000101111
3221211020002012102101
421110103311120233
5130442112421033
64332421235531
7502630111444
oct112423653057
927736065371
1010004420143
114274263a23
121b32562ba7
13c358a7343
146ac9939cb
153d848297d
hex2544f562f

10004420143 has 4 divisors (see below), whose sum is σ = 10005263320. Its totient is φ = 10003576968.

The previous prime is 10004420053. The next prime is 10004420171. The reversal of 10004420143 is 34102440001.

10004420143 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10004420143 - 213 = 10004411951 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10004420143.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10004450143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403533 + ... + 427606.

It is an arithmetic number, because the mean of its divisors is an integer number (2501315830).

Almost surely, 210004420143 is an apocalyptic number.

10004420143 is a deficient number, since it is larger than the sum of its proper divisors (843177).

10004420143 is an equidigital number, since it uses as much as digits as its factorization.

10004420143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 843176.

The product of its (nonzero) digits is 384, while the sum is 19.

Adding to 10004420143 its reverse (34102440001), we get a palindrome (44106860144).

The spelling of 10004420143 in words is "ten billion, four million, four hundred twenty thousand, one hundred forty-three".

Divisors: 1 12037 831139 10004420143