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10004432101 = 36432746207
BaseRepresentation
bin10010101000100111…
…11000010011100101
3221211020002210211021
421110103320103211
5130442113311401
64332421411141
7502630161346
oct112423702345
927736083737
1010004432101
114274271a04
121b32569ab1
13c358ac911
146ac9980cd
153d84862a1
hex2544f84e5

10004432101 has 4 divisors (see below), whose sum is σ = 10007181952. Its totient is φ = 10001682252.

The previous prime is 10004432089. The next prime is 10004432143. The reversal of 10004432101 is 10123440001.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10123440001 = 19352453057.

It is a cyclic number.

It is not a de Polignac number, because 10004432101 - 25 = 10004432069 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10004432171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1369461 + ... + 1376746.

It is an arithmetic number, because the mean of its divisors is an integer number (2501795488).

Almost surely, 210004432101 is an apocalyptic number.

It is an amenable number.

10004432101 is a deficient number, since it is larger than the sum of its proper divisors (2749851).

10004432101 is an equidigital number, since it uses as much as digits as its factorization.

10004432101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2749850.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 10004432101 its reverse (10123440001), we get a palindrome (20127872102).

The spelling of 10004432101 in words is "ten billion, four million, four hundred thirty-two thousand, one hundred one".

Divisors: 1 3643 2746207 10004432101