Base | Representation |
---|---|
bin | 11101000111100101010… |
… | …00000110111101000101 |
3 | 10112122110202221010212011 |
4 | 32203302220012331011 |
5 | 112343012232410224 |
6 | 2043342535454221 |
7 | 132166253202541 |
oct | 16436250067505 |
9 | 3478422833764 |
10 | 1000503013189 |
11 | 356346960179 |
12 | 141aa2527371 |
13 | 73468567294 |
14 | 365d3184a21 |
15 | 1b05a9c7394 |
hex | e8f2a06f45 |
1000503013189 has 2 divisors, whose sum is σ = 1000503013190. Its totient is φ = 1000503013188.
The previous prime is 1000503013177. The next prime is 1000503013277. The reversal of 1000503013189 is 9813103050001.
1000503013189 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 817156337089 + 183346676100 = 903967^2 + 428190^2 .
It is a cyclic number.
It is not a de Polignac number, because 1000503013189 - 231 = 998355529541 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1000503013189.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1000503083189) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500251506594 + 500251506595.
It is an arithmetic number, because the mean of its divisors is an integer number (500251506595).
Almost surely, 21000503013189 is an apocalyptic number.
It is an amenable number.
1000503013189 is a deficient number, since it is larger than the sum of its proper divisors (1).
1000503013189 is an equidigital number, since it uses as much as digits as its factorization.
1000503013189 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 31.
The spelling of 1000503013189 in words is "one trillion, five hundred three million, thirteen thousand, one hundred eighty-nine".
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