Base | Representation |
---|---|
bin | 101110100101101110… |
… | …1111111101101010011 |
3 | 100120020200111000222022 |
4 | 1131023131333231103 |
5 | 3114400400332011 |
6 | 113543523202055 |
7 | 10141225246331 |
oct | 1351335775523 |
9 | 316220430868 |
10 | 100050402131 |
11 | 39481930a59 |
12 | 1748281632b |
13 | 95860a8ba4 |
14 | 4bb1a20b51 |
15 | 29088938db |
hex | 174b77fb53 |
100050402131 has 2 divisors, whose sum is σ = 100050402132. Its totient is φ = 100050402130.
The previous prime is 100050402121. The next prime is 100050402149. The reversal of 100050402131 is 131204050001.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-100050402131 is a prime.
It is a super-2 number, since 2×1000504021312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (100050402121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50025201065 + 50025201066.
It is an arithmetic number, because the mean of its divisors is an integer number (50025201066).
Almost surely, 2100050402131 is an apocalyptic number.
100050402131 is a deficient number, since it is larger than the sum of its proper divisors (1).
100050402131 is an equidigital number, since it uses as much as digits as its factorization.
100050402131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 100050402131 its reverse (131204050001), we get a palindrome (231254452132).
The spelling of 100050402131 in words is "one hundred billion, fifty million, four hundred two thousand, one hundred thirty-one".
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