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10005043109911 is a prime number
BaseRepresentation
bin1001000110010111101100…
…0010100110000000010111
31022102110202122201210001221
42101211323002212000113
52302410312014004121
633140130420231211
72051561203151533
oct221457302460027
938373678653057
1010005043109911
11320812a006153
12115706483b507
13577618bcc325
14268364c12bc3
151253c2a62b41
hex9197b0a6017

10005043109911 has 2 divisors, whose sum is σ = 10005043109912. Its totient is φ = 10005043109910.

The previous prime is 10005043109839. The next prime is 10005043110071. The reversal of 10005043109911 is 11990134050001.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10005043109911 - 27 = 10005043109783 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10005043139911) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002521554955 + 5002521554956.

It is an arithmetic number, because the mean of its divisors is an integer number (5002521554956).

Almost surely, 210005043109911 is an apocalyptic number.

10005043109911 is a deficient number, since it is larger than the sum of its proper divisors (1).

10005043109911 is an equidigital number, since it uses as much as digits as its factorization.

10005043109911 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4860, while the sum is 34.

Adding to 10005043109911 its reverse (11990134050001), we get a palindrome (21995177159912).

The spelling of 10005043109911 in words is "ten trillion, five billion, forty-three million, one hundred nine thousand, nine hundred eleven".