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100055103120 = 2433573135049
BaseRepresentation
bin101110100101110111…
…1111011011010010000
3100120021000022212112000
41131023233323122100
53114403101244440
6113544212034000
710141313226000
oct1351357733220
9316230285460
10100055103120
1139484551975
1217484302900
13958706383b
144bb24c6000
152908ec1730
hex174bbfb690

100055103120 has 320 divisors, whose sum is σ = 401908800000. Its totient is φ = 22869568512.

The previous prime is 100055103119. The next prime is 100055103133. The reversal of 100055103120 is 21301550001.

100055103120 is a `hidden beast` number, since 100 + 0 + 5 + 510 + 31 + 20 = 666.

It is a super-2 number, since 2×1000551031202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 100055103093 and 100055103102.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 673356 + ... + 808404.

It is an arithmetic number, because the mean of its divisors is an integer number (1255965000).

Almost surely, 2100055103120 is an apocalyptic number.

100055103120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 100055103120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200954400000).

100055103120 is an abundant number, since it is smaller than the sum of its proper divisors (301853696880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

100055103120 is a wasteful number, since it uses less digits than its factorization.

100055103120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 135092 (or 135066 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

Adding to 100055103120 its reverse (21301550001), we get a palindrome (121356653121).

The spelling of 100055103120 in words is "one hundred billion, fifty-five million, one hundred three thousand, one hundred twenty".