Base | Representation |
---|---|
bin | 101110100101111000… |
… | …0000100101100010111 |
3 | 100120021000101210200021 |
4 | 1131023300010230113 |
5 | 3114403104004033 |
6 | 113544212530011 |
7 | 10141313444566 |
oct | 1351360045427 |
9 | 316230353607 |
10 | 100055141143 |
11 | 394845784a1 |
12 | 17484320907 |
13 | 9587077c39 |
14 | 4bb24d5bdd |
15 | 2908eccb2d |
hex | 174bc04b17 |
100055141143 has 4 divisors (see below), whose sum is σ = 100101061240. Its totient is φ = 100009221048.
The previous prime is 100055141119. The next prime is 100055141171. The reversal of 100055141143 is 341141550001.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 100055141143 - 225 = 100021586711 is a prime.
It is a super-2 number, since 2×1000551411432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (100052141143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22956780 + ... + 22961137.
It is an arithmetic number, because the mean of its divisors is an integer number (25025265310).
Almost surely, 2100055141143 is an apocalyptic number.
100055141143 is a deficient number, since it is larger than the sum of its proper divisors (45920097).
100055141143 is an equidigital number, since it uses as much as digits as its factorization.
100055141143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45920096.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 100055141143 its reverse (341141550001), we get a palindrome (441196691144).
The spelling of 100055141143 in words is "one hundred billion, fifty-five million, one hundred forty-one thousand, one hundred forty-three".
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