Base | Representation |
---|---|
bin | 10010101000110000… |
… | …01001001110010101 |
3 | 221211022012121020221 |
4 | 21110120021032111 |
5 | 130442410044343 |
6 | 4332501354341 |
7 | 502642525426 |
oct | 112430111625 |
9 | 27738177227 |
10 | 10005549973 |
11 | 4274965871 |
12 | 1b32a089b1 |
13 | c35bb1693 |
14 | 6acba964d |
15 | 3d86075ed |
hex | 254609395 |
10005549973 has 2 divisors, whose sum is σ = 10005549974. Its totient is φ = 10005549972.
The previous prime is 10005549959. The next prime is 10005550031. The reversal of 10005549973 is 37994550001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9734190244 + 271359729 = 98662^2 + 16473^2 .
It is a cyclic number.
It is not a de Polignac number, because 10005549973 - 25 = 10005549941 is a prime.
It is a super-2 number, since 2×100055499732 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10005549913) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5002774986 + 5002774987.
It is an arithmetic number, because the mean of its divisors is an integer number (5002774987).
Almost surely, 210005549973 is an apocalyptic number.
It is an amenable number.
10005549973 is a deficient number, since it is larger than the sum of its proper divisors (1).
10005549973 is an equidigital number, since it uses as much as digits as its factorization.
10005549973 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 170100, while the sum is 43.
The spelling of 10005549973 in words is "ten billion, five million, five hundred forty-nine thousand, nine hundred seventy-three".
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