Search a number
-
+
10006504153 = 83120560291
BaseRepresentation
bin10010101000110111…
…10010001011011001
3221211101000002010221
421110123302023121
5130443131113103
64332534040041
7502653611332
oct112433621331
927741002127
1010006504153
114275457748
121b331a9021
13c36156a99
146acd77289
153d87451bd
hex2546f22d9

10006504153 has 4 divisors (see below), whose sum is σ = 10127064528. Its totient is φ = 9885943780.

The previous prime is 10006504141. The next prime is 10006504163. The reversal of 10006504153 is 35140560001.

10006504153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10006504153 - 217 = 10006373081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10006504163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60280063 + ... + 60280228.

It is an arithmetic number, because the mean of its divisors is an integer number (2531766132).

Almost surely, 210006504153 is an apocalyptic number.

It is an amenable number.

10006504153 is a deficient number, since it is larger than the sum of its proper divisors (120560375).

10006504153 is an equidigital number, since it uses as much as digits as its factorization.

10006504153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 120560374.

The product of its (nonzero) digits is 1800, while the sum is 25.

The spelling of 10006504153 in words is "ten billion, six million, five hundred four thousand, one hundred fifty-three".

Divisors: 1 83 120560291 10006504153