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10009944001153 is a prime number
BaseRepresentation
bin1001000110101001111100…
…1010000000101010000001
31022102221102012121211222101
42101222133022000222001
52303000331131014103
633142301011310401
72052123513065305
oct221523712005201
938387365554871
1010009944001153
11320a214480298
121157bb1bab401
13577c1a369c85
142686aba75d05
151255ace3da1d
hex91a9f280a81

10009944001153 has 2 divisors, whose sum is σ = 10009944001154. Its totient is φ = 10009944001152.

The previous prime is 10009944001091. The next prime is 10009944001219. The reversal of 10009944001153 is 35110044990001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6867790698609 + 3142153302544 = 2620647^2 + 1772612^2 .

It is an emirp because it is prime and its reverse (35110044990001) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10009944001153 - 241 = 7810920745601 is a prime.

It is not a weakly prime, because it can be changed into another prime (10009942001153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5004972000576 + 5004972000577.

It is an arithmetic number, because the mean of its divisors is an integer number (5004972000577).

Almost surely, 210009944001153 is an apocalyptic number.

It is an amenable number.

10009944001153 is a deficient number, since it is larger than the sum of its proper divisors (1).

10009944001153 is an equidigital number, since it uses as much as digits as its factorization.

10009944001153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19440, while the sum is 37.

Adding to 10009944001153 its reverse (35110044990001), we get a palindrome (45119988991154).

The spelling of 10009944001153 in words is "ten trillion, nine billion, nine hundred forty-four million, one thousand, one hundred fifty-three".