1001000000053 has 2 divisors, whose sum is σ = 1001000000054. Its totient is φ = 1001000000052.

The previous prime is 1001000000017. The next prime is 1001000000093. The reversal of 1001000000053 is 3500000001001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 979420977649 + 21579022404 = 989657^2 + 146898^2 .

It is a cyclic number.

It is not a de Polignac number, because 1001000000053 - 2⁹ = 1000999999541 is a prime.

It is a super-2 number, since 2×1001000000053² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1000999999976 and 1001000000039.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1001000000093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500000026 + 500500000027.

It is an arithmetic number, because the mean of its divisors is an integer number (500500000027).

Almost surely, 2^{1001000000053} is an apocalyptic number.

It is an amenable number.

1001000000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001000000053 is an equidigital number, since it uses as much as digits as its factorization.

1001000000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 10.

Adding to 1001000000053 its reverse (3500000001001), we get a palindrome (4501000001054).

The spelling of 1001000000053 in words is "one trillion, one billion, fifty-three", and thus it is an aban number and an uban number.