1001000131 has 2 divisors, whose sum is σ = 1001000132. Its totient is φ = 1001000130.

The previous prime is 1001000113. The next prime is 1001000141. The reversal of 1001000131 is 1310001001.

It is a happy number.

1001000131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (1001000113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1001000131 - 2⁹ = 1000999619 is a prime.

It is a super-3 number, since 3×1001000131³ (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1001000111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 500500065 + 500500066.

It is an arithmetic number, because the mean of its divisors is an integer number (500500066).

Almost surely, 2^1001000131 is an apocalyptic number.

1001000131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1001000131 is an equidigital number, since it uses as much as digits as its factorization.

1001000131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 7.

The square root of 1001000131 is about 31638.5861093697. The cubic root of 1001000131 is about 1000.3332659215. Note that the first 3 decimals are identical.

Adding to 1001000131 its reverse (1310001001), we get a palindrome (2311001132).

The spelling of 1001000131 in words is "one billion, one million, one hundred thirty-one", and thus it is an aban number.