100100110099981 has 2 divisors, whose sum is σ = 100100110099982. Its totient is φ = 100100110099980.

The previous prime is 100100110099961. The next prime is 100100110099991. The reversal of 100100110099981 is 189990011001001.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85641605775625 + 14458504324356 = 9254275^2 + 3802434^2 .

It is a cyclic number.

It is not a de Polignac number, because 100100110099981 - 2¹⁵ = 100100110067213 is a prime.

It is a super-3 number, since 3×100100110099981³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (100100110099961) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050055049990 + 50050055049991.

It is an arithmetic number, because the mean of its divisors is an integer number (50050055049991).

Almost surely, 2^{100100110099981} is an apocalyptic number.

It is an amenable number.

100100110099981 is a deficient number, since it is larger than the sum of its proper divisors (1).

100100110099981 is an equidigital number, since it uses as much as digits as its factorization.

100100110099981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5832, while the sum is 40.

The spelling of 100100110099981 in words is "one hundred trillion, one hundred billion, one hundred ten million, ninety-nine thousand, nine hundred eighty-one".