Base | Representation |
---|---|
bin | 10110110000101001100000… |
… | …000110110111001000101101 |
3 | 111010102110220111011021102012 |
4 | 112300221200012313020231 |
5 | 101110020021233241023 |
6 | 552521205502211005 |
7 | 30040665202664135 |
oct | 2660514006671055 |
9 | 433373814137365 |
10 | 100100120212013 |
11 | 2999324a289349 |
12 | b2880a7883a65 |
13 | 43b1529824c4c |
14 | 1aa0c2bc05ac5 |
15 | b88c79352978 |
hex | 5b0a601b722d |
100100120212013 has 2 divisors, whose sum is σ = 100100120212014. Its totient is φ = 100100120212012.
The previous prime is 100100120211991. The next prime is 100100120212049. The reversal of 100100120212013 is 310212021001001.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96841384003204 + 3258736208809 = 9840802^2 + 1805197^2 .
It is a cyclic number.
It is not a de Polignac number, because 100100120212013 - 222 = 100100116017709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (100100120218013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050060106006 + 50050060106007.
It is an arithmetic number, because the mean of its divisors is an integer number (50050060106007).
Almost surely, 2100100120212013 is an apocalyptic number.
It is an amenable number.
100100120212013 is a deficient number, since it is larger than the sum of its proper divisors (1).
100100120212013 is an equidigital number, since it uses as much as digits as its factorization.
100100120212013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 100100120212013 its reverse (310212021001001), we get a palindrome (410312141213014).
The spelling of 100100120212013 in words is "one hundred trillion, one hundred billion, one hundred twenty million, two hundred twelve thousand, thirteen".
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