100100211200051 has 2 divisors, whose sum is σ = 100100211200052. Its totient is φ = 100100211200050.

The previous prime is 100100211199993. The next prime is 100100211200053. The reversal of 100100211200051 is 150002112001001.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 100100211200051 - 2⁶ = 100100211199987 is a prime.

Together with 100100211200053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 100100211199999 and 100100211200035.

It is not a weakly prime, because it can be changed into another prime (100100211200053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50050105600025 + 50050105600026.

It is an arithmetic number, because the mean of its divisors is an integer number (50050105600026).

Almost surely, 2^{100100211200051} is an apocalyptic number.

100100211200051 is a deficient number, since it is larger than the sum of its proper divisors (1).

100100211200051 is an equidigital number, since it uses as much as digits as its factorization.

100100211200051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20, while the sum is 14.

Adding to 100100211200051 its reverse (150002112001001), we get a palindrome (250102323201052).

The spelling of 100100211200051 in words is "one hundred trillion, one hundred billion, two hundred eleven million, two hundred thousand, fifty-one".