10010061433 has 2 divisors, whose sum is σ = 10010061434. Its totient is φ = 10010061432.

The previous prime is 10010061353. The next prime is 10010061443. The reversal of 10010061433 is 33416001001.

10010061433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9910600704 + 99460729 = 99552^2 + 9973^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10010061433 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 10010061433.

It is not a weakly prime, because it can be changed into another prime (10010061443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005030716 + 5005030717.

It is an arithmetic number, because the mean of its divisors is an integer number (5005030717).

Almost surely, 2^10010061433 is an apocalyptic number.

It is an amenable number.

10010061433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010061433 is an equidigital number, since it uses as much as digits as its factorization.

10010061433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10010061433 its reverse (33416001001), we get a palindrome (43426062434).

The spelling of 10010061433 in words is "ten billion, ten million, sixty-one thousand, four hundred thirty-three".