10010110101113 has 2 divisors, whose sum is σ = 10010110101114. Its totient is φ = 10010110101112.

The previous prime is 10010110101109. The next prime is 10010110101143. The reversal of 10010110101113 is 31110101101001.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6127842800704 + 3882267300409 = 2475448^2 + 1970347^2 .

It is a cyclic number.

It is not a de Polignac number, because 10010110101113 - 2² = 10010110101109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10010110101094 and 10010110101103.

It is not a weakly prime, because it can be changed into another prime (10010110101143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005055050556 + 5005055050557.

It is an arithmetic number, because the mean of its divisors is an integer number (5005055050557).

Almost surely, 2^{10010110101113} is an apocalyptic number.

It is an amenable number.

10010110101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010110101113 is an equidigital number, since it uses as much as digits as its factorization.

10010110101113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 10010110101113 its reverse (31110101101001), we get a palindrome (41120211202114).

The spelling of 10010110101113 in words is "ten trillion, ten billion, one hundred ten million, one hundred one thousand, one hundred thirteen".