Base | Representation |
---|---|
bin | 1001000110101010100100… |
… | …1011010101101000111011 |
3 | 1022102221211220222020121022 |
4 | 2101222221023111220323 |
5 | 2303001202200341103 |
6 | 33142325414533055 |
7 | 2052130624064642 |
oct | 221525113255073 |
9 | 38387756866538 |
10 | 10010112121403 |
11 | 320a2a0369549 |
12 | 115803a36718b |
13 | 577c46141804 |
14 | 2686c611a359 |
15 | 1255bca9c138 |
hex | 91aa92d5a3b |
10010112121403 has 2 divisors, whose sum is σ = 10010112121404. Its totient is φ = 10010112121402.
The previous prime is 10010112121351. The next prime is 10010112121409. The reversal of 10010112121403 is 30412121101001.
10010112121403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10010112121403 - 212 = 10010112117307 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (10010112121409) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005056060701 + 5005056060702.
It is an arithmetic number, because the mean of its divisors is an integer number (5005056060702).
Almost surely, 210010112121403 is an apocalyptic number.
10010112121403 is a deficient number, since it is larger than the sum of its proper divisors (1).
10010112121403 is an equidigital number, since it uses as much as digits as its factorization.
10010112121403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 10010112121403 its reverse (30412121101001), we get a palindrome (40422233222404).
The spelling of 10010112121403 in words is "ten trillion, ten billion, one hundred twelve million, one hundred twenty-one thousand, four hundred three".
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