Base | Representation |
---|---|
bin | 101110100111001111… |
… | …1100011001101000010 |
3 | 100120101012221212001022 |
4 | 1131032133203031002 |
5 | 3120001343010224 |
6 | 113552534505442 |
7 | 10142412443066 |
oct | 1351637431502 |
9 | 316335855038 |
10 | 100101141314 |
11 | 394a8537069 |
12 | 17497805282 |
13 | 9593762885 |
14 | 4bb866baa6 |
15 | 290d06765e |
hex | 174e7e3342 |
100101141314 has 4 divisors (see below), whose sum is σ = 150151711974. Its totient is φ = 50050570656.
The previous prime is 100101141311. The next prime is 100101141319. The reversal of 100101141314 is 413141101001.
100101141314 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 96034911025 + 4066230289 = 309895^2 + 63767^2 .
It is a junction number, because it is equal to n+sod(n) for n = 100101141292 and 100101141301.
It is not an unprimeable number, because it can be changed into a prime (100101141311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025285327 + ... + 25025285330.
Almost surely, 2100101141314 is an apocalyptic number.
100101141314 is a deficient number, since it is larger than the sum of its proper divisors (50050570660).
100101141314 is an equidigital number, since it uses as much as digits as its factorization.
100101141314 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50050570659.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 100101141314 its reverse (413141101001), we get a palindrome (513242242315).
The spelling of 100101141314 in words is "one hundred billion, one hundred one million, one hundred forty-one thousand, three hundred fourteen".
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