10010121983 has 2 divisors, whose sum is σ = 10010121984. Its totient is φ = 10010121982.

The previous prime is 10010121973. The next prime is 10010122037. The reversal of 10010121983 is 38912101001.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10010121983 is a prime.

It is a super-2 number, since 2×10010121983² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10010121923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5005060991 + 5005060992.

It is an arithmetic number, because the mean of its divisors is an integer number (5005060992).

Almost surely, 2^10010121983 is an apocalyptic number.

10010121983 is a deficient number, since it is larger than the sum of its proper divisors (1).

10010121983 is an equidigital number, since it uses as much as digits as its factorization.

10010121983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 26.

Adding to 10010121983 its reverse (38912101001), we get a palindrome (48922222984).

The spelling of 10010121983 in words is "ten billion, ten million, one hundred twenty-one thousand, nine hundred eighty-three".